What formula can be used to calculate the resistance of a load using power and current values?

What formula can be used to calculate the resistance of a load using power and current values?

• A. R = P / V
• B. R = I^2 / P
• C. R = P / I^2
• D. R = V / I

Answer: (C)

The formula used to calculate the resistance of a load using power and current values is \( R = \frac{P}{I^2} \). In this formula, \( P \) represents the power in watts, and \( I \) represents the current in amperes. This relationship can be derived from the basic principles of electrical power. The power consumed by a resistive load can also be expressed using Ohm’s Law, which states that \( V = I \times R \) and that power can be calculated as \( P = V \times I \). By substituting Ohm’s Law into the power equation, we find: \[ P = (I \times R) \times I \] \[ P = I^2 \times R \] To find resistance, we rearrange the equation to isolate \( R \): \[ R = \frac{P}{I^2} \] This formula clearly shows how resistance can be determined when you know the power consumed by the load and the current flowing through it. Using the other options would not yield the correct relationship for resistance when using power and current values specifically. The resistance calculated using this formula is critical not just for theoretical understanding,

The formula used to calculate the resistance of a load using power and current values is ( R = \frac{P}{I^2} ). In this formula, ( P ) represents the power in watts, and ( I ) represents the current in amperes.

This relationship can be derived from the basic principles of electrical power. The power consumed by a resistive load can also be expressed using Ohm’s Law, which states that ( V = I \times R ) and that power can be calculated as ( P = V \times I ). By substituting Ohm’s Law into the power equation, we find:

[

P = (I \times R) \times I

]

[

P = I^2 \times R

]

To find resistance, we rearrange the equation to isolate ( R ):

[

R = \frac{P}{I^2}

]

This formula clearly shows how resistance can be determined when you know the power consumed by the load and the current flowing through it.

Using the other options would not yield the correct relationship for resistance when using power and current values specifically. The resistance calculated using this formula is critical not just for theoretical understanding,